What is the probability of that child getting a green marble.
There are 9 red and 6 green marbles.
At this moment the bag becomes the same as it is before a green marble is drawn i e.
Write the probability as a fraction in simplest form a decimal and a percent.
There s two red marbles in the bag.
4 20 then find the probability of picking green again 3 19.
Jun 21 2018 1 3 explanation.
1 answer jim g.
There are a total of 14 green and blue marbles so the probability is 14 25 or 56.
So i could pick that green marble or that green marble.
Solution from the condition we can determine how many marbles of each color were there in the jar.
Finally multiply the probabilities and reduce to get 3 95 share.
Be careful letting children play with marbles they may swallow.
A child reaches in the bag and randomly takes one marble.
9 blue marbles 8 green marbles 4 red marbles 8 white marbles and 6 yellow marbles.
There are 35 marbles in a bag.
And then there s one blue marble in the bag.
There s one blue marble.
There are 9 red and 6 green marbles in a bag.
As both requirements have to be fulfilled the required probability is the multiplication of both 6 15 6 15.
What is the probability of drawing a green marble from the bag.
So this is all the possible outcomes.
The measure of probability is number of favourable outcomes total possible outcomes a favourable outcome is a green marble of which there are 6.
There are still 6 green marbles and 9 red ones.
You wish to know t probability that the single chosen green or blue marble.
There s two green marbles in the bag.
In the bag there are 6 green marbles and 12 red marbles.
There are 9 red and 6 green marbles in a bag if a child reaches the bag randomly and picks 6.
So i could pick that red marble or that red marble.
There are 6 red 4 green 5 blue and 5 yellow marbles in a jar.
The total number of marbles in the box is 25 that is 9 green 5 blue and 11 red.
Indeed we have these equations where r is the number of red marbles g is the number.
Remember there is one less marble in the jar and that you assume the marble picked was green.
7 red 5 green 6 blue pick 7 6 1 14 marbles and at least 1 is red because 14 green blue 11 at least 1 is blue because 14 red green 12 at least 1 is green because 14 red blue 13 picking 13 marbles could result in green marble absence if all 13 marbl.
These are clearly all yellow.